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Solve the following pair of linear equations by the substituti(i) s-t=30 x+y= 14S+x-y=4(iii) 3x - y = 39x - 3y=9(iv) 0.2x+0.3y = 1.30.4x +0.5y = 2.3(1) √2x+√3 y=0√x - √8y=0 |
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Answer» cross multiplication method x= 9, s= 39-4t, 6(3x- y) = 18 1. x = 9, y = 5 answer gudankhand vidhi se lagega first answer 7+ 7 =14 second 7 - 4 = 3 My answer is x = 0 , y = 0 question no:-1 y=5,x=9 1 (i) x+y=14 _(i) x-y=4 (ii) (i) +(ii) we get x =9Then putting the value of x in eqn (i) we get y=5 X=9,y= 5 is right answer 1 questions2ques And X= 9and y= 6ok question (1)===. x=9 y=5 1 x+y = 14x = -y+14slu.. 2 me man rakhane par x-y = 4-y+14-y =4-2y =4-14-2y =-102y =10 y = 5 slu..1 ya 2 me man rakhne perx+y =14x+5=14x =14-5x = 9 ANSWER X == 9 AND Y ==5 X=4+yx+y=144+y+y=142y=14-42y=10y=10/2=5X=4+y =4+5 =9 Ans- x=0 y=0 2nd, 6th me pehle LCM lena hai phir Elimination,Substitution,cross-multiplication kisi bhi method se kar sakte ho aap Tamar malni kai mhar bhi ni malm 1- y =5 and x=92- s= 9 and t= 63- y= 3x-3 and x can be anything4- x=2and y=35- x=0 and y=06- x=2 and y=3 x=9, y=5s=39-4t6(3x-y)=183x-y=3 ( i ) x=9 y=5 ( ii ) s=9 t=6 ( iii ) 9=9 I don't know you questions 1)x=9 y=52)x=1 y=03)4)5)6) by substitution method a 1 b 1 c 14a 1 b -1 c 4 x=9, s=39-4t, 6$3x-y)=18 x+y=14. x+y=14. ------ (i)x-y=4. ------- (ii) samikaran (i) sex=14-ysamikaran(ii)me x-y=4or, 14-y-y=4or, 14-2y=4or, 14-4=2yor, 10/2 =y y=5. ans.x-y=4x-5=4x=4+5x=9 1- x=9 and y=5 first add eq(1)& |
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