1.

Solve the following pair of linear equations by the substitution method .​

Answer»

Answer:

Take LCM of 3x/2-5y/3

9x-10y/6= -2

9x-10y=-2×6

9x-10y= -12 _equation 1 ST

Now take LCM of x/3 +y/2

2x+3y/6= 13/6

2x+3y= 13/6×6

2x+3y= 78/6 _ equation 2 ND

By USING substitution METHOD

Now multiple equation 1st by 18 and equation 2 nd by 10 then add equation 1 St and 2 nd

162x -180y= -216

120x+180y=780

__________________

282x = 564

X= 564/282= 2

Put the value of X in equation 1 St

9x -10y = -12

9×2-10y= -12

18-10y=-12

-10y=-12-18

-10y= - 30

y= -30/-10

y= 3

Therefore X= 2 and y= 3


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