1.

Solve the following pair of linear equations by theelimination method.x+3/5y=-18/53/2x+2y=-5/2

Answer»

Answer:

x=−57/11 and y= 29/11

Step-by-step explanation:

first multiply it by 10...

10(x+3/5y=−18/5)

−3(3/2x+2y=−5/2)

Becomes:

10x+6y=−36

−9/2x−6y=15/2

Then...

Add these EQUATIONS to ELIMINATE y:

11/2

x=−57/2

Then SOLVE

11/2

x=−57/2

for x:11/2

x=

−57

--------

2

--------

11

--------

2

x

11

2

=

−57

2

11

2

(Divide both SIDES by 11/2)

x=

−57

11

Now that we've found x let's plug it BACK in to solve for y.

Write down an original equation:

x+

3

5

y=

−18

5

Substitute

−57

11

forxinx+

3

5

y=

−18

5

:

−57

11

+

3

5

y=

−18

5

3

5

y+

−57/11=−18/5

(Simplify both sides of the equation)

y+(3/5)−57/11+57/11

=−18/5+57/11

(Add 57/11 to both sides)

3/5

y=87/55

y(3/5)/3/5

=

87/55/3/5

(Divide both sides by 3/5)

y=29/11

IDK...


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