Solve the following pair of linear equations by substitution method:0.

1.	Solve the following pair of linear equations by substitution method:0.5x + 0.8y = 3.40.6x — 0.3y = 0.3
Answer» Given equations are 0.5x + 0.8y = 3.4 …(i) 0.6x – 0.3y = 0.3 …(ii) From eqⁿ (ii), 2x – y = 1 y = 2x – 1 …(iii) On substituting y = 0.2x – 1 in eqⁿ (i), we get ⇒ 0.5x + 0.8(2x – 1) = 3.4 ⇒ 0.5x + 1.6x – 0.8 = 3.4 ⇒ 2.1x = 3.4 + 0.8 ⇒ 2.1x = 4.2 ⇒ x = 4.2/2.1 = 2 Now, on putting x = 2 in eqⁿ (iii), we get ⇒ y = 2(2) – 1 ⇒ y = 4 – 1 ⇒ y = 3 Thus, x = 2 and y = 3 is the required solution.

Solve the following pair of linear equations by substitution method:0.5x + 0.8y = 3.40.6x — 0.3y = 0.3

Answer»

Given equations are

0.5x + 0.8y = 3.4 …(i)

0.6x – 0.3y = 0.3 …(ii)

From eqⁿ (ii), 2x – y = 1

y = 2x – 1 …(iii)

On substituting y = 0.2x – 1 in eqⁿ (i), we get

⇒ 0.5x + 0.8(2x – 1) = 3.4

⇒ 0.5x + 1.6x – 0.8 = 3.4

⇒ 2.1x = 3.4 + 0.8

⇒ 2.1x = 4.2

⇒ x = 4.2/2.1 = 2

Now, on putting x = 2 in eqⁿ (iii), we get

⇒ y = 2(2) – 1

⇒ y = 4 – 1

⇒ y = 3

Thus, x = 2 and y = 3 is the required solution.