Solve the following pair of equations. 1x+3y=1 6x−12y=2 (where x≠0

1.	Solve the following pair of equations. 1x+3y=1 6x−12y=2 (where x≠0,y≠0)
Answer» Solve the following pair of equations. $\frac{1}{x} + \frac{3}{y} = 1$ $\frac{6}{x} - \frac{12}{y} = 2$ (where $x \neq 0, y \neq 0)$

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