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Solve the following(i) log 32 = x

Answer»

log 2 32=2^5( 32=2^5

We know, if log x (base y)=a then x = y^aSo, log 32 (base 2) = ximplies2^x = 32 = 2^5x = 5.

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the correct answer X=5

log^2 32=zso 2 is the base then value if x=5

the correct answer after solving comes x=5

x=5 is the correct answer.



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