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Solve the following equations by trial and error method:(ii) 3m – 14 = 4 |
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Answer» 3m – 14 = 4 Solution:− LHS = 3m – 14 By substituting the value of m = 3 Then, LHS = 3m – 14 = (3 × 3) – 14 = 9 – 14 = – 5 By COMPARING LHS and RHS -5 ≠ 4 LHS ≠ RHS Hence, the value of m = 3 is not a solution to the given equation. Let, m = 4 LHS = 3m – 14 = (3 × 4) – 14 = 12 – 14 = – 2 By comparing LHS and RHS -2 ≠ 4 LHS ≠ RHS Hence, the value of m = 4 is not a solution to the given equation. Let, m = 5 LHS = 3m – 14 = (3 × 5) – 14 = 15 – 14 = 1 By comparing LHS and RHS 1 ≠ 4 LHS ≠ RHS Hence, the value of m = 5 is not a solution to the given equation. |
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