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Solve the following equation by using factorisation method4x2-4ax + (a2-b2) = 0.ICBSE 2012. 15

Answer»

4x^2-4ax+(a^2-b^2)=0

=> (4x^2-4ax+a^2)-b^2=0

=>(2x-a)^2-b^2=0

=>{2x-a-b}{2x-a+b}=0

=> x=(a+b)/2 , (a-b)/2



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