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Solve the following differential equation: ` x(dy)/(dx)-y=2 sqrt(y^2-x^2)` |
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Answer» Correct Answer - `1/2log_(e)y+sqrt(y^(2)-x^(2))/(x)=log_(e)cx` Putting `y=vx` and `(dy)/(dx)=v+x(dv)/(dx)`, we get `xv+x^(2)(dv)/(dx)=vx+2xsqrt(v^(2)-1)` or `int(dv)/(2sqrt(v^(2)-1))=int(dx)/x`, Integrating, we get `1/2" ln "(v+sqrt(v^(2)-1))="ln "cx` or `1/2"ln "(y+sqrt(y^(2)-x^(2)))/x="ln "cx` |
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