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Solve the equation and verify your answer:((x+2) (2x-3) – 2x2 + 6)/(x-5) = 2 |
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Answer» We have, ((x+2) (2x-3) – 2x2 + 6)/(x-5) = 2 By cross-multiplying we get, (x+2) (2x-3) – 2x2 + 6) = 2(x-5) 2x2 – 3x + 4x – 6 – 2x2 + 6 = 2x – 10 x = 2x – 10 x – 2x = -10 -x = -10 x = 10 Now let us verify the given equation, ((x+2) (2x-3) – 2x2 + 6)/(x-5) = 2 By substituting the value of ‘x’ we get, ((10+2) (2(10) – 3) – 2(10)2 + 6)/ (10-5) = 2 (12(17) – 200 + 6)/5 = 2 (204 – 194)/5 = 2 10/5 = 2 2 = 2 Hence, the given equation is verified. |
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