1.

Solve the equation and verify your answer:((x+2) (2x-3) – 2x2 + 6)/(x-5) = 2

Answer»

We have,

((x+2) (2x-3) – 2x2 + 6)/(x-5) = 2

By cross-multiplying we get,

(x+2) (2x-3) – 2x2 + 6) = 2(x-5)

2x2 – 3x + 4x – 6 – 2x2 + 6 = 2x – 10

x = 2x – 10

x – 2x = -10

-x = -10

x = 10

Now let us verify the given equation,

((x+2) (2x-3) – 2x2 + 6)/(x-5) = 2

By substituting the value of ‘x’ we get,

((10+2) (2(10) – 3) – 2(10)2 + 6)/ (10-5) = 2

(12(17) – 200 + 6)/5 = 2

(204 – 194)/5 = 2

10/5 = 2

2 = 2

Hence, the given equation is verified.



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