Solve the differential equation`sinxdy/dx+3y=cosx` – InterviewSolution

1.	Solve the differential equation`sinxdy/dx+3y=cosx`
Answer» `dy/dx+(3y)/sinx=cosx/sinx` `P(x)=3/sinx` `Q(x)=cotx` `IF=e^(intp(x)dx)=e^(3/sinx) dx=e^(3intcosecx)`dx `=e^(ln(1+cosecx+cotx)^(-3)` `yIF=intIFQ(x) dx` `=int-dt/t^3` `=-(t^(-4+1)/(-4+1))` `y*if=1/(3(cosecx+cotx)^3` `y=1/((cosecx+cotx)^3^3(cosecx+cotx)^3)` `y=1/3`.

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