1.

Solve the above problem, if 20 V battery is connected with unlike polarities together.

Answer»

`4 XX 10^(-4) J`
`9 xx 10^(-4) J`
`2 xx 10^(-4) J`
`10^(-4) J`

Solution :`q_(1)=20 muC U_(1)=10^(-4) J q_(2)=40 muC`
`U_(2)=4 xx10^(-4) J Delta Q=20+40 =60 muC`
(because, polarity has charged)
W.D by the BATTERY `= 20 xx60 xx10^(-6)=12 xx 10^(-4)J`
Heat `=U_(1)-U_(2)+W.D`
`= 10^(-4)-4 xx10^(-4) +12 xx10^(-4) =9 xx10^(-4)J`.


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