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Solve sinx^2 by first principle method. |
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Answer» Answer: F(x) = sin (x) f(x+h) = sin(x+h) From first PRINCIPLE, d(f(x))/DX = lim h->0 [ f(x+h) - f(x) ] /h Now, d(sinx)/dx = lim h->0 sin(x+h) - sin(x) / h = lim h->0 2 cos ( x + h/2) sin h/2 / h = lim h->0 (2/2) (cos ( x + h/2) )* (sin h/2 / h/2) = Lim h->0 cos ( x + h/2) = cos x Hence PROVED from first principle that d(sin x)/dx = cos x |
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