Solve sec^2 alpha + tan^2 alpha = 5/3 – InterviewSolution

1.

Solve sec^2 alpha + tan^2 alpha = 5/3

Answer»

Step-by-step EXPLANATION:

sec^2 ALPHA - tan^2 alpha + 2tan^2 alpha = 5/3

1 + 2tan^2alpha = 5/3

2tan ^2 alpha = 5/3 -1

tan^2alpha = 1/3

tan alpha = 1/root3

alpha = 30 DEGREE

Discussion

No Comment Found

Related InterviewSolutions

What is Rational Numbers ??Where are you Bunny ?? What happen Any Problem Bro ಠ︵ಠ
Observe the following table and find x is directly proportional
What is Rational Numbers ?Answer if ur boy ? Answer if ur Ashrith Im serious
ABCD is a parallelogram if the ratio sides 3,:2and perimeter is 120 m the find the length of the sides of the parallelogram
6. Find the area of the following polygohABCDEF where AP = 2 cm, AQ = 4 cm,AR = 6 cm, AD = 10 cm, AS = 8 cm, andBP, FQ, CR and ES are perpendiculars todiagonal AD
5y+10=4y-10 then what is the answer
*5. How do the prashastis written by Harisena and Ravikirti throw light on the history of theGuptas and Harshavardhana?
The product of two number is 27 /2 .If one number is 23/5,find the other. with solution
Evalute the expression given below for ( m = - 2 ) & ( n = 6 ) 3m³ + 2m²n + n³
Evalute the expression given below for ( m = - 2 ) & ( n = 6 )m² - n²