Solve Q7 step by step in copy

1.	Solve Q7 step by step in copy
Answer» Height from which the ball was DROPPED = 20m acceleration = 10m/s² As the ball is dropped, its initial velocity, u = 0m/s From LAWS of motion, → v² - u² = 2as → v² = 2as → v² = 2 (10) (20) → v = 20 m/s Now, v = u + at → 20 = 0 + (10)t → 10t = 20 → t = 2 seconds Therefore, 2 seconds after being dropped, the ball will strike the GROUND with a velocity of 20 m/s Hope it helps!!

Answer»

Height from which the ball was DROPPED = 20m

acceleration = 10m/s²

As the ball is dropped, its initial velocity, u = 0m/s

From LAWS of motion,

→ v² - u² = 2as

→ v² = 2as

→ v² = 2 (10) (20)

→ v = 20 m/s

Now, v = u + at

→ 20 = 0 + (10)t

→ 10t = 20

→ t = 2 seconds

Therefore, 2 seconds after being dropped, the ball will strike the GROUND with a velocity of 20 m/s

Hope it helps!!

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Solve Q7 step by step in copy

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