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Solve log4 2power8x = 2log 2power8 |
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Answer» Let x denote the REQUIRED LOGARITHM. Therefore, log2√3 1728 = x or, (2√3)x = 1728 = 26 ∙ 33 = 26 ∙ (√3)6 or, (2√3)x = (2√3)6 Therefore, x = 6. |
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