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Solve `log_4 (8)+log_4 (x+3)-log_4 (x-1)=2` |
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Answer» `log_(4)^(8)+log_(4)(x+3)-log_(4)(x-1)=2` `or"log"_(4) (8(x+3))/(x-1)=2` or `(8(x+3))/(x-1)=4^(2)` `orx+3=2x-2` `rArr" "x=5` Also for x=5 all terms of the equation are defined. |
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