Saved Bookmarks
| 1. |
Solve : $$\\lim_{x \\to 1} \\left(\\dfrac{3x^2 +2x + 1}{x^2 - 1} \\right)$$ |
|
Answer» $$\\lim_{x \\to 1} \\left(\\dfrac{3x^2 +2x + 1}{x^2 - 1 } \\right)= $$\\left(\\dfrac{16}{0} \\right)= $$\\left(\\dfrac{3x^2 +2x + 1}{(x+1)(x-1)} \\right)= I don\'t know what to do next ??? \\lim_{x \\to 1} \\left(\\dfrac{3x^2 +2x + 1}{x^2 - 1 } \\right)= \\left(\\dfrac{16}{0} \\right)= \\left(\\dfrac{3x^2 +2x + 1}{(x+1)(x-1)} \\right)= I don\'t know what to do next ??? Done Coding challenge?????? |
|