Solve it⤵tan(65-θ) - cot(25+θ) = tan{90-(25+θ)} Also tell value o

1.	Solve it⤵tan(65-θ) - cot(25+θ) = tan{90-(25+θ)} Also tell value of tan{90-(25+θ)}
Answer» Therefore, this should be CALCULATED by = { As we KNOW, Tan θ = Cot ( 90 - θ ) , so :- }We get, Tan [ 90 - ( 65 + θ ) ] - Cot ( 25 - θ ) Cot [ 25 - θ ] - Cot ( 25 - θ)= 0. Hope..this ANSWER may help you..plz..mark it as BRAINLIST....

Solve it⤵tan(65-θ) - cot(25+θ) = tan{90-(25+θ)} Also tell value of tan{90-(25+θ)}

Answer»

Therefore, this should be CALCULATED by = { As we KNOW, Tan θ = Cot ( 90 - θ ) , so :- }We get, Tan [ 90 - ( 65 + θ ) ] - Cot ( 25 - θ ) Cot [ 25 - θ ] - Cot ( 25 - θ)= 0.

Hope..this ANSWER may help you..plz..mark it as BRAINLIST....

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Solve it⤵tan(65-θ) - cot(25+θ) = tan{90-(25+θ)} Also tell value of tan{90-(25+θ)}​

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Solve it⤵tan(65-θ) - cot(25+θ) = tan{90-(25+θ)} Also tell value of tan{90-(25+θ)}