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Solve it:tan^-1 (cotx) + cot^-1 (tanx) = π/4​

Answer»

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Step-by-step explanation:

TAN^-1(tan(pi/2-x))+COT^-1(cot(pi/2-x))=pi/4

so,pi/2-x+pi/2-x=pi/4

pi-2x=-pi/4

-2x=pi/4-pi

-2x=-3pi/4

x=3pi/8



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