Let usual speed = xTotal distance = 300km◆ time taken= 300/xNew speed of train is x+5time taken= 300/x+5A/q 300/x-300/x+5=2 hrs300x+1500-300x/x(x+5). = 21500=2x2+10x2x2+10x-1500=0x2+5x-750=0(x+30)(x+25)=0but 30 is REJECTED ANSWERthe CORRECT answer is 25kmphokkkphle WRONG tha now you can mark me as brainiest
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