1.

Solve it plzzzz its urgent

Answer»

Let usual speed = x
Total distance = 300km

◆ time taken= 300/x
New speed of train is x+5

time taken= 300/x+5

A/q

300/x-300/x+5=2 hrs

300x+1500-300x/x(x+5). = 2

1500=2x2+10x

2x2+10x-1500=0

x2+5x-750=0

(x+30)(x+25)=0

but 30 is REJECTED ANSWER

the CORRECT answer is 25kmph

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