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Solve it plz guys...... |
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Answer» •♫•.ENERGY of the INCIDENT Photon is given by ,E = hc/ lemda = 1242eV / 300nm = 4.14 eV in HYDROGEN atom the electron can be excited to the first excited STATE if it absorbs energy equal to - 13.6eV/2^2-(-13.6/1^2) eV - 13.6/4+13.6= 10.2eV тℏᾰℵкṧ |
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