Solve it...........

1.	Solve it...........
Answer» ANSWER: VALUE of P(y) at y = 0 is 3. GIVEN: P(y) = 5y-4y²+3 TO FIND: Value of above EXPRESSION at y = 0. SOLUTION: => P(y) = 5y-4y²+3 Finding P(y) at y = 0. => P(0) = 5(0)-4(0)²+3 => P(0) = 0-0+3 => P(0) = 3 Value of P(y) at y = 0 is 3. NOTE: Some IMPORTANT formulas: (a+b)(a-b) = a²-b² (a+b)³ = a³+b³+3ab(a+b) (a-b)³ = a³-b³-3ab(a-b) a³+b³ = (a+b)(a²+b²-ab) a³-b³ = (a-b)(a²+b²+ab) (a+b)² = (a-b)²+4ab (a-b)² = (a+b)²-4ab

Answer»

ANSWER:

VALUE of P(y) at y = 0 is 3.

GIVEN:

P(y) = 5y-4y²+3

TO FIND:

Value of above EXPRESSION at y = 0.

SOLUTION:

=> P(y) = 5y-4y²+3

Finding P(y) at y = 0.

=> P(0) = 5(0)-4(0)²+3

=> P(0) = 0-0+3

=> P(0) = 3

Value of P(y) at y = 0 is 3.

NOTE:

Some IMPORTANT formulas:

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab

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