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Solve he question number 9 |
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Answer» Answer: 9) p(X)=5x^4-5x³-33x²+3x+18=0 two of the zeroes are √3/5 and -√3/5 (x-√3/5)*(x+√3/5) x²-3/5 or 5x²-3 will be a FACTOR of p(x) by long division we get x²-x-6 x²-x-6=0 (x²-3x)(+2x-6)=0 x(x-3)+2(x-3)=0 (x+2)(x-3)=0 x=-2,3 so,-2 and 3 are the two other zeroes of the p(x) HOPE it helps PLEASE mark as brainliest Step-by-step explanation: |
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