1.

Solve for x and y ,41x+31y=63and 31x+47y=15

Answer»

47x+31y=63(eqn 1)

31x+47y=15(eqn 2)

adding both eqn,we get

78x+78y=78

dividing this eqn by 78,we get

x+y=1 (be it eqn 3)

SUBTRACTING eqn 1 and eqn 2,we get

16x-16y=48

dividing this eqn by 16, we get

x-y=3(be it eqn 4)

using elimination method for eqn 3and eqn4

x+y=1

x-y=3

2x=4

x=2

putting value of x in x+y=1,by solving we get

y=-(negative)1

therefore

x=2

y=-1

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