1.

Solve for x and y 3x+y+1=0 and 2x-3y+8 =0​

Answer»

Step-by-step explanation:

GIVEN -

3x + y + 1 = 0

2X - 3Y + 8 = 0

To Find -

Value of x and y

Now,

3x + y = - 1

2x - 3y = - 8

Using Substitution method,

3x + y = - 1

  • y = - 1 - 3x

Substituting the value of y on

2x - 3y = - 8

= 2x - 3(- 1 - 3x) = - 8

= 2x + 3 + 9x = - 8

= 11x = - 8 - 3

= 11x = - 11

= x = -11/11

  • = x = - 1

Now,

Substituting the value of x on

3x + y = - 1

= 3(- 1) + y = - 1

= - 3 + y = - 1

= y = - 1 + 3

  • = y = 2

Hence,

The value of x is - 1

and

The value of y is 2

Verification -

Substituting the value of x and y on 3x + y = - 1

= 3(- 1) + 2 = - 1

= - 3 + 2 = - 1

= - 1 = - 1

LHS = RHS

Now,

Substituting the value of x and y on 2x - 3y = - 8

= 2(- 1) - 3(2) = - 8

= - 2 - 6 = - 8

= - 8 = - 8

LHS = RHS

Hence,

Verified..


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