Solve for x and y: 3x - 5y - 19 = 0, -7x + 3y + 1 = 0

1.	Solve for x and y: 3x - 5y - 19 = 0, -7x + 3y + 1 = 0
Answer» The given system of equation is: 3x - 5y - 19 = 0 ……(i) - 7x + 3y + 1 = 0 ……(ii) On multiplying (i) by 3 and (ii) by 5, we get: 9x - 15y = 57 ……(iii) - 35x + 15y = -5 …….(iv) On subtracting (iii) from (iv) we get: - 26x = (57 – 5) = 52 ⇒ x = - 2 On substituting the value of x = - 2 in (i), we get: –6 – 5y – 19 = 0 ⇒ 5y = (–6 – 19) = -25 ⇒ y = -5 Hence, the solution is x = -2 and y = - 5.

Answer»

The given system of equation is:

3x - 5y - 19 = 0 ……(i)

- 7x + 3y + 1 = 0 ……(ii)

On multiplying (i) by 3 and (ii) by 5, we get:

9x - 15y = 57 ……(iii)

- 35x + 15y = -5 …….(iv)

On subtracting (iii) from (iv) we get:

- 26x = (57 – 5) = 52

⇒ x = - 2

On substituting the value of x = - 2 in (i), we get:

–6 – 5y – 19 = 0

⇒ 5y = (–6 – 19) = -25

⇒ y = -5

Hence, the solution is x = -2 and y = - 5.

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