1.

Solve for x=2x/x-5+5(2x/x-5

Answer»

X= 4x^2/(x-5)^2+10x/(x-5)-24
x= 4x^2/(x-5)^2 + 10x/(x-5)-24
on TAKING LCM...
and USING IDENTITY (a-b)^2= a^2+b^2-2ab
= 4x^2+10x(x-5)-24(x-5)^2
= 4x^2+10x^2-50x-24(x^2+25-10x)
= 4x^2+10x^2-50x-24x^2-600+240x
= (4+10-24)x^2+(-50+240)x-600
= -10x^2+(190)x-600
10x^2-190x+600=0
taking out 10 common
we get,
10(x^2-19x+60)=0
x^2-15x-4x+60=0
x(x-15)-4(x-15)=0
therefore
(x-4)(x-15)=0
the value of x is 4 and 15
hope this helps you.....


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