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Solve equations by using the substitution method.0.2x + 0.3y =1.3 0.4x + 0.5y = 2.3 |
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Answer» Given: 0.2x + 0.3y = 1.3 ⇒ 2x + 3y = 13 …… (1) 0.4x + 0.5y = 2.3 ⇒ 4x + 5y = 23 …… (2) From equation (1) 2x = 13 – 3y ⇒ x = \(\frac{13-3y}{2}\) Substituting x = \(\frac{13-3y}{2}\) equation (2) we get \(\frac{13-3y}{2}\) + 5y = 23 ⇒ 26 – 6y + 5y = 23 ⇒ -y + 26 = 23 ⇒ y = 26 — 23 = 3 Substituting y = 3 in equaion (1) we get 2x + 3(3) = 13 ⇒ 2x + 9 = 13 ⇒ 2x = 13 – 9 ⇒ 2x = 4 ⇒ x = 4/2 = 2 ∴ The solution is (2, 3) |
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