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Solve each of the following in equations and represent the solution set on the number line.\(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) ≥0 x ϵ R. –{–2, 2} |
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Answer» Given: \(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) ≥0 x ϵ R. –{–2, 2} Intervals of |x|: x ≥ 0, |x| = x and x < 0, |x| = -x Domain of \(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) ≥ 0 \(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) is not defined for x = -2 and x = 2 Therefore, Domain: x < -2 or -2 < x < 2 or x > 2 Combining intervals with domain: x < 2, -2<x<0, 0≤x<2, x≤2 For x < -2: \(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) = \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\ge\)0 Signs of – x – 1: -x -1 = 0 → x = -1 (Adding 1 to both the sides and then dividing by -1 on both the sides) -x – 1> 0 → x < -1 (Adding 1 to both the sides and then multiplying by -1 on both the sides) -x – 1 < 0 → x > -1 (Adding 1 to both the sides and then multiplying by -1 on both the sides) Signs of – x – 2: -x -2 = 0 → x = -2 (Adding 2 to both the sides and then dividing by -1 on both the sides) -x – 2> 0 → x < -2 (Adding 2 to both the sides and then multiplying by -1 on both the sides) -x – 2 < 0 → x > -2 (Adding 2 to both the sides and then multiplying by -1 on both the sides) Intervals satisfying the required condition: ≥ 0 x < - 2 or x = -1 or x > -1 Merging overlapping intervals: x < -2 or x ≥ -1 Combining the intervals: x < -2 or x ≥ -1 and x < -2 Merging overlapping intervals: x < -2 Similarly, for -2 < x < 0: \(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) = \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\ge\)0 Therefore, Intervals satisfying the required condition: ≥ 0 x < - 2 or x = -1 or x > -1 Merging overlapping intervals: x < -2 or x ≥ -1 Combining the intervals: x < -2 or x ≥ -1 and -2 < x < 0 Merging overlapping intervals: -1 ≤ x < 0 For 0 ≤ x < 2, \(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) = \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\ge\)0 Signs of x – 1: x – 1 = 0 → x = 1(Adding 1 to both the sides) x – 1 > 0 → x > 1(Adding 1 to both the sides) x – 1 < 0 → x < 1(Adding 1 to both the sides) Signs of x – 2: x – 2 = 0 → x = 2(Adding 2 to both the sides) x – 2 < 0 → x < 2(Adding 2 to both the sides) x – 2 > 0 → x > 2(Adding 2 to both the sides) At x = 2, \(\cfrac{x-1}{x-2}\) is not defined Intervals satisfying the required condition: ≥ 0 x < 1 or x = 1 or x > 2 Merging overlapping intervals: x ≤ 1 or x > 2 Combining the intervals: x ≤ 1 or x > 2 and 0 ≤ x < 2 Merging overlapping intervals: 0 ≤ x ≤ 1 Similarly, for x > 2: \(\frac{|{\text{x}} |-1}{|{\text{x}} |-2}\) = \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\frac{-{\text{x}} -1}{-{\text{x}} -2}\) \(\ge\)0 Therefore, Intervals satisfying the required condition: ≥ 0 x < 1 or x = 1 or x > 2 Merging overlapping intervals: x ≤ 1 or x > 2 Combining the intervals: x ≤ 1 or x > 2 and x > 2 Merging overlapping intervals: x > 2 Combining all the intervals: x < -2 or -1 ≤ x < 0 or 0 ≤ x ≤ 1 or x >2 Merging the overlapping intervals: x < -2 or -1 ≤ x ≤ 1 or x > 2 Therefore x ϵ (-∞, -2) Ս [-1,1] Ս (2, ∞) |
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