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Solve `(dy)/(dx)=cos(x+y)-sin(x+y)`. |
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Answer» Correct Answer - `-log_(e)|1-tan(x+y)/(2)|=x+c` `(dy)/(dx) = cos(x+y)-sin(x+y)` Putting `x+y=t`, we get `(dy)/(dx)=(dt)/(dx)-1` Therefore, `(dt)/(dx)-1=cost-sint` or `(dt)/(1+cost-sint)=dx` or `(sec^(2)t/2dt)/(2(1-tant/2))=dx` or `-"ln "|1-tan(x+y)/(2)|=x+c` |
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