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Solve c part of question 1 by step by step simultaneous equation |
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Answer» let 1/(x+1) =a 1/(y-1) =b we get 20a+4b=5 and 10a-4b=1 solving these TWO equations by elimination method 4b and -4b GETS cancelled we get 30a=6 a=6/30 a=1/5 substituting a value in one equation 20(1/5) +4b=5 4+4b=5 4b=5-4 b=1/4 we 1/(x+1) =1/5 x+1=5 x=4 1/y-1=1/4 y-1=4 y=5 |
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