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Answer» It is GIVEN that 99x+101y = 499 101x+99y = 501 Here we have to follow 2 cases Addition n subtraction So now we COULD add 99x+ 101y = 499 101x+ 99y = 501 When we add we will get 200x+ 200y = 1000 If we take 200 common , we will get 200(x+y)= 1000 x+y= 1000÷200 x+y=5.......equation(1) Now to 2nd CASE..we need to subtract 99x-101y=499 101x-99y=501 On subtracting we'll get -2x+2y= -2 -2(x-y) = -2 x-y = -2÷ -2 x-y = 1........ equation (2) Now USING elimination method solve x+y = 5 (+) x-y = 1 We'll get x=3 and y=2 Now substitute x and y and check whether these values are corrct
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