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Solve:\(5x-\frac{1}{3}(x+1)=6(x+\frac{1}{30})\)5x - 1/3 (x + 1) = 6(x + 1/30) |
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Answer» \(5x-\frac{1}{3}(x+1)=6(x+\frac{1}{30})\) Taking LCM on both the sides \(\frac{15x-(x+1)}{3}=\frac{6(30x+1)}{30}\) By cross multiplication ⇒ 10(14x - 1) = 6(30x + 1) ⇒ 140x - 180x = 6 + 10 ⇒ - 40x = 16 ⇒ \(\text{x}=-\frac{2}{5}\) |
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