1.

Solve : 3 (2×– 7) =5 (3× +8)​

Answer»

Answer:

LCM of 3,6,9=18

Now LET US CHANGE each of the given FRACTION into an equivalent fraction having 18 as the DENOMINATOR.

(2/3)x(6/6)=(12/18)

and (5/6)x(3/3)=(15/18)

and (1/9)x(2/2)=(2/18)

Now,

=(12/18)+(15/18)−(2/18)

=(12+15−2)/18

=(27−2)/18

=(25/18)

=[1(7/18)]


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