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Solve (2xy-y²-y)dx+(2xy-x²-x)dy=0 |
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Answer» ong>Answer: answer is 12 Step-by-step explanation: becauseGiven, d(X 2 y)=d(XY)+d(xy 2 ) ⇒x 2 y=xy+xy 2 +c At x=1,y=1 ⇒ c = -1 ⇒x 2 y=xy+xy 2 −1⇒y=−y+y 2 −1 ∴y 2 +2y+1=0⇒y=−1 ∴12y∣y(−1)∣=12 |
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