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Solve: `|-2x^2+1+e^x+sinx|=2x^2-1|+e^x+|sinx|,x in [0,2pi]dot` |
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Answer» `|-2x^(2)+1+e^(x)+sinx|=|2x^(2)-1|+e^(x)+|sinx|, x in [0,2pi]` in the R.H.S., each term is positive and `e^(x) gt 0.` So, `1-2x^(2) ge 0` and ` sin x ge 0` or `x in [-(1)/(sqrt(2)),(1)/(sqrt(2))] and x in [0,pi]` ` :. x in [0,(1)/(sqrt(2))]` |
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