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Solve:- 2cos²x+3sinx=0#Dont spam​

Answer» 2 Cos[2]x + 3 SINX = 0
2 ( 1 - Sin[2]x ) + 3 Sinx = 0
2 Sin[2]x - 3 Sinx - 2 = 0
2 Sin[2]x - 4 Sinx + Sinx - 2 = 0
( 2 Sinx + 1 ) ( Sinx - 2 ) = 0

Sinx = -1/2 = Sin 120 => x = 120

Sinx = 2


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