1.

Solve 2^x+3 = 4^x-1 find value of x​

Answer»

Answer:

5.

Step-by-step explanation:

⇒ 2^( x + 3 ) = 4^( x - 1 )

⇒ 2^( x + 3 ) = ( 2^2 )^( x - 1 )

⇒ 2^( x + 3 ) = 2^{ 2( x - 1 ) }

⇒ 2^( x + 3 ) = 2^( 2x - 2 )

        Powers of two, both sides, must be EQUAL.

⇒ x + 3 = 2x - 2

⇒ 3 + 2 = 2x - x

⇒ 5 = x

      HENCE the required value of x is 5.

 Few terms used here :

          4 = 2^2  { in 2nd step, RHS }

          ( a^n )^m = a^( NM )     { in 3nd step, RHS }


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