solve 11x-9y+4=06x-5y+3=0 by substitution method – InterviewSolution

1.

solve 11x-9y+4=06x-5y+3=0 by substitution method

Answer»

11x - 9y + 4 = 09y = (11x + 4)y = (11x + 4)/9........(1)

6x - 5y = - 3..............(2)

Put value of y from eq(1) in eq(2)6x - 5*(11x + 4)/9 = - 354x - 55x - 20 = - 27-x = - 27 + 20x = 7

Now,From eq(1)y = (11*7 + 4)/9 = 81/9 = 9

Therefore, value of x = 7 and y = 9

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