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Solve 10sin⁴x + 15cos⁴x = 6 find the value of 27 cosec^6x + 8sec^6x ?? |
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Answer» Answer: 10sin⁴x + 15cos⁴x = 6 10sin⁴x+15cos⁴x = 6(sin²x+cos²x) 10tan⁴x + 15=6(tan²x+1)² so by dividing by cos⁴x (2tan²x -3)² =0 tan²x =3/2 27cosec^6x + 8se'^6x 27(1+cost²x)³+8(1+tan²x) 27(1+2/3)³+8(1+3/2)² 27× 125/27 +8*(125/8) =250 how it HELPS you |
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