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Solve...(01) x(3x^2- 19) = 2(x^2 - 11) |
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Answer» Let's SOLVE your equation step-by-step. x(3x²−19)=2(x²−11) 3x³−19x=2x²−22 Step 1: Subtract 2x²-22 from both sides. 3x³−19x−(2x²−22)=2x²−22−(2x²−22) 3x³−2x²−19x+22=0 Step 2: Factor left side of equation. (x−2)(3x²+4x−11)=0 Step 3: Set FACTORS EQUAL to 0. x−2=0 or 3x²+4x−11=0 x=2 or x=1.3609208434327398 or x=−2.694254176766073 Answer: x=2 or x=1.3609208434327398 or x=−2.694254176766073
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