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Solution of the equation `cos^(2)x+cos^(2)2x+cos^(2)3x=1` isA. `x=(2m+1)(pi)/2(m in I)`B. `x=(2n+1)(pi)/4(n in I)`C. `x=(2k+1)(pi)/6(k in I)`D. `x=(2l+1)(pi)/8(l in I)` |
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Answer» Correct Answer - A::B::C Equation can be written as `cos2x(cos 4x+cos2x)=0` `implies 2cos x cos 2x cos 3x=0` |
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