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Solution of calcium phosphate (molecular mass, M) in water is w g per at `25^(@)`C, its solubility product at `25^(@)`C will be approximately :-A. `10^(9)((W)/(M))^(5)`B. `10^(7)((W)/(M))^(5)`C. `10^(5)((W)/(M))^(5)`D. `10^(3)((W)/(M))^(5)` |
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Answer» Correct Answer - B `{:(Ca_(3)(PO_(4))_(2),hArr,3Ca^(+2),+,2PO_(4)^(-2)),(" "S,,3S,,2S):}` 100ml have = w gm 100 ml have `(w)/(100)xx1000=(wxx10)(M)`(solubility) Now Ksp = `[Ca^(+2)]^(3)[PO_(4)^(-2)]^(2)` `rArr[(wxx10xx3)/(M)]^(3)[(wxx10xx2)/(M)]^(2)` Approx `= 10^(7)((w)/(M))^(5)` |
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