1.

Solue the following differential equationdy/dx =​

Answer»

Answer:

\frac{dy}{dx} = \frac{ \sqrt{1 - {y}^{2} } }{ \sqrt{1 - {x}^{2} } }

\frac{dy}{ \sqrt{1 - {y}^{2} } } = \frac{dx}{ \sqrt{1 - {x}^{2} } }

INTEGRATING both SIDES, we get

\sin {}^{ - 1} (y) = \sin {}^{ - 1} (x) + c

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