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Solubility (s) of `CaF_(2)` in terms of its solubility product is given asA. `s = (K_(sp))^(1//3)`B. `s = (K_(sp)//2)^(1//3)`C. `s = (K_(sp)//4)^(1//3)`D. `s = (K_(sp)//2)^(1//2)` |
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Answer» Correct Answer - C It is ternary electrolyte, `CaF_(2) harr Ca^(2+) + 2F^(-)` Let solubility of `CaF_(2)` be s mol `"litre"^(-1)` Then `{:(CaF_(2) hArr,Ca^(2+),+,2F^(-)),(,s,,2s):}` Let `K_(sp) = [Ca^(2+)] [F^(-)]^(2) = (s) xx (2s)^(2) = 4s^(3)` `s = sqrt((K_(sp))/(4))`. |
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