Saved Bookmarks
| 1. |
Solid NH I dissociates according to the reaction at 400 KNH,I(s) NH,(g) + HI(g); K = 16 atm. In presence ofcatalyst HI dissociates in H, and I, as 2H H+1,. Ifpartial pressure of H, at this temp is 1 atm in the containerwhen both the equilibrium exist simultaneously, calculate Kvalue of second equilibrium (for the dissociation of HI). |
|
Answer» Answer: NH,I(s) NH,(g) + HI(g); K = 16 atm. In PRESENCE of catalyst HI dissociates in H, and I, as 2H H+1,. If partial pressure of H, at this temp is 1 atm in the container when both the equilibrium exist simultaneously, |
|