1.

Solid NH I dissociates according to the reaction at 400 K NH,I(s) NH,(g) + HI(g); K = 16 atm. In presence ofcatalyst HI dissociates in H, and I, as 2H H+1,. Ifpartial pressure of H, at this temp is 1 atm in the containerwhen both the equilibrium exist simultaneously, calculate Kvalue of second equilibrium (for the dissociation of HI).​

Answer»

ong>Answer:

NH,I(s) NH,(g) + HI(g); K = 16 ATM. In PRESENCE of

catalyst HI DISSOCIATES in H, and I, as 2H H+1,. If

partial pressure of H, at this TEMP is 1 atm in the container

when both the equilibrium exist simultaneously,



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