Solid BaF2 is added to a solution that has 0.3 mole of a sodium oxalate solution (1 litre) until equilibrium is reached. The Ksp of BaF2 and BaC2O4(s) is 10−6 and 2×10−7 respectively. Assume that the addition of BaF2 does not cause any change in the volume and causes no hydrolysis of any of the cations or anions. If the concentration of Ba2+ ions in the resulting solution at equilibrium is represented as y×10−x, then (x+y) is:

Solid BaF2 is added to a solution that has 0.3 mole of a sodium oxalat

1.	Solid BaF2 is added to a solution that has 0.3 mole of a sodium oxalate solution (1 litre) until equilibrium is reached. The Ksp of BaF2 and BaC2O4(s) is 10−6 and 2×10−7 respectively. Assume that the addition of BaF2 does not cause any change in the volume and causes no hydrolysis of any of the cations or anions. If the concentration of Ba2+ ions in the resulting solution at equilibrium is represented as y×10−x, then (x+y) is:
Answer» Solid $B a F_{2}$ is added to a solution that has 0.3 mole of a sodium oxalate solution (1 litre) until equilibrium is reached. The $K_{s p}$ of $B a F_{2}$ and $B a C_{2} O_{4} (s)$ is $10^{- 6}$ and $2 \times 10^{- 7}$ respectively. Assume that the addition of $B a F_{2}$ does not cause any change in the volume and causes no hydrolysis of any of the cations or anions. If the concentration of $B a^{2 +}$ ions in the resulting solution at equilibrium is represented as $y \times 10^{- x}$ , then $(x + y)$ is: