Solenoid of length 10 cm and radius 1 cm contains 200 turns and carrie

1.	Solenoid of length 10 cm and radius 1 cm contains 200 turns and carries a current of 10 ampere the value of pole strength of each pole is
Answer» Answer: $M = 2\pi Am$ Explanation: The pole strength is the product of NUMBER of turns per UNIT LENGTH , AREA and current. Given that, Length l = 0.1 m Radius r = 0.01 m Number of turns per unit length $n = \dfrac{N}{l} = \dfrac{200}{0.1}$ Current in the solenoid i = 10 A The pole strength is M = nIA $M = \dfrac{200}{0.1}\times10 A\times \pi\times 0.01m\times0.01m$ $M = 2\pi Am$ $M = 2\pi Am$ Hence, the pole strength is .

Solenoid of length 10 cm and radius 1 cm contains 200 turns and carries a current of 10 ampere the value of pole strength of each pole is

Answer»

Answer: $M = 2\pi Am$

Explanation: The pole strength is the product of NUMBER of turns per UNIT LENGTH , AREA and current.

Given that,

Length l = 0.1 m

Radius r = 0.01 m

Number of turns per unit length $n = \dfrac{N}{l} = \dfrac{200}{0.1}$

Current in the solenoid i = 10 A

The pole strength is

M = nIA

$M = \dfrac{200}{0.1}\times10 A\times \pi\times 0.01m\times0.01m$

$M = 2\pi Am$

$M = 2\pi Am$ Hence, the pole strength is .

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Solenoid of length 10 cm and radius 1 cm contains 200 turns and carries a current of 10 ampere the value of pole strength of each pole is

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